5[-3(2x+3)+4(4x-5)]=

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Solution for 5[-3(2x+3)+4(4x-5)]= equation:


Simplifying
5[-3(2x + 3) + 4(4x + -5)] = 0

Reorder the terms:
5[-3(3 + 2x) + 4(4x + -5)] = 0
5[(3 * -3 + 2x * -3) + 4(4x + -5)] = 0
5[(-9 + -6x) + 4(4x + -5)] = 0

Reorder the terms:
5[-9 + -6x + 4(-5 + 4x)] = 0
5[-9 + -6x + (-5 * 4 + 4x * 4)] = 0
5[-9 + -6x + (-20 + 16x)] = 0

Reorder the terms:
5[-9 + -20 + -6x + 16x] = 0

Combine like terms: -9 + -20 = -29
5[-29 + -6x + 16x] = 0

Combine like terms: -6x + 16x = 10x
5[-29 + 10x] = 0
[-29 * 5 + 10x * 5] = 0
[-145 + 50x] = 0

Solving
-145 + 50x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '145' to each side of the equation.
-145 + 145 + 50x = 0 + 145

Combine like terms: -145 + 145 = 0
0 + 50x = 0 + 145
50x = 0 + 145

Combine like terms: 0 + 145 = 145
50x = 145

Divide each side by '50'.
x = 2.9

Simplifying
x = 2.9

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